Integrand size = 22, antiderivative size = 307 \[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c}+\frac {e \left (56 c^2 d^2+15 b^2 e^2-2 c e (25 b d+8 a e)+6 c e (2 c d-b e) x\right ) \sqrt [4]{a+b x+c x^2}}{10 c^3}+\frac {\sqrt [4]{b^2-4 a c} (2 c d-b e) \left (4 c^2 d^2+3 b^2 e^2-4 c e (b d+2 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} c^{13/4} (b+2 c x)} \]
[Out]
Time = 0.24 (sec) , antiderivative size = 307, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {756, 793, 637, 226} \[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\frac {\sqrt [4]{b^2-4 a c} \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (2 a e+b d)+3 b^2 e^2+4 c^2 d^2\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} c^{13/4} (b+2 c x)}+\frac {e \sqrt [4]{a+b x+c x^2} \left (-2 c e (8 a e+25 b d)+15 b^2 e^2+6 c e x (2 c d-b e)+56 c^2 d^2\right )}{10 c^3}+\frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c} \]
[In]
[Out]
Rule 226
Rule 637
Rule 756
Rule 793
Rubi steps \begin{align*} \text {integral}& = \frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c}+\frac {2 \int \frac {(d+e x) \left (\frac {1}{4} \left (10 c d^2-e (b d+8 a e)\right )+\frac {9}{4} e (2 c d-b e) x\right )}{\left (a+b x+c x^2\right )^{3/4}} \, dx}{5 c} \\ & = \frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c}+\frac {e \left (56 c^2 d^2+15 b^2 e^2-2 c e (25 b d+8 a e)+6 c e (2 c d-b e) x\right ) \sqrt [4]{a+b x+c x^2}}{10 c^3}+\frac {\left ((2 c d-b e) \left (4 c^2 d^2+3 b^2 e^2-4 c e (b d+2 a e)\right )\right ) \int \frac {1}{\left (a+b x+c x^2\right )^{3/4}} \, dx}{8 c^3} \\ & = \frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c}+\frac {e \left (56 c^2 d^2+15 b^2 e^2-2 c e (25 b d+8 a e)+6 c e (2 c d-b e) x\right ) \sqrt [4]{a+b x+c x^2}}{10 c^3}+\frac {\left ((2 c d-b e) \left (4 c^2 d^2+3 b^2 e^2-4 c e (b d+2 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{2 c^3 (b+2 c x)} \\ & = \frac {2 e (d+e x)^2 \sqrt [4]{a+b x+c x^2}}{5 c}+\frac {e \left (56 c^2 d^2+15 b^2 e^2-2 c e (25 b d+8 a e)+6 c e (2 c d-b e) x\right ) \sqrt [4]{a+b x+c x^2}}{10 c^3}+\frac {\sqrt [4]{b^2-4 a c} (2 c d-b e) \left (4 c^2 d^2+3 b^2 e^2-4 c e (b d+2 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{4 \sqrt {2} c^{13/4} (b+2 c x)} \\ \end{align*}
Time = 10.25 (sec) , antiderivative size = 193, normalized size of antiderivative = 0.63 \[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\frac {-2 c e (a+x (b+c x)) \left (-15 b^2 e^2+2 c e (25 b d+8 a e+3 b e x)-4 c^2 \left (15 d^2+5 d e x+e^2 x^2\right )\right )-5 \sqrt {2} \sqrt {b^2-4 a c} (-2 c d+b e) \left (4 c^2 d^2+3 b^2 e^2-4 c e (b d+2 a e)\right ) \left (\frac {c (a+x (b+c x))}{-b^2+4 a c}\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arcsin \left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ),2\right )}{20 c^4 (a+x (b+c x))^{3/4}} \]
[In]
[Out]
\[\int \frac {\left (e x +d \right )^{3}}{\left (c \,x^{2}+b x +a \right )^{\frac {3}{4}}}d x\]
[In]
[Out]
\[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac {3}{4}}} \,d x } \]
[In]
[Out]
\[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\int \frac {\left (d + e x\right )^{3}}{\left (a + b x + c x^{2}\right )^{\frac {3}{4}}}\, dx \]
[In]
[Out]
\[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac {3}{4}}} \,d x } \]
[In]
[Out]
\[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac {3}{4}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {(d+e x)^3}{\left (a+b x+c x^2\right )^{3/4}} \, dx=\int \frac {{\left (d+e\,x\right )}^3}{{\left (c\,x^2+b\,x+a\right )}^{3/4}} \,d x \]
[In]
[Out]